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pentoo/gentoo

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51x 6 years ago
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  1. 166
      lui_pentoo.sh

166
lui_pentoo.sh

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#!/bin/bash
# LUI for Pentoo - Version 2.1.6b
#
# Description: This script searches and organizes information about users on Pentoo/Gentoo systems. It is written to make administration easier and for better transparency.
#
# Note: this program has been tested on Pentoo 4.6.
#
# Author: 51x
# License: GNU AFFERO GENERAL PUBLIC LICENSE - Version 3, 19 November 2007
#
# Copyright (C) 2016 51x
#
# This program is free software: you can redistribute it and/or modify
# it under the terms of the GNU Affero General Public License as published
# by the Free Software Foundation, either version 3 of the License, or
# (at your option) any later version.
#
# This program is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the
# GNU Affero General Public License for more details.
#
# You should have received a copy of the GNU Affero General Public License
# along with this program. If not, see <http://www.gnu.org/licenses/>.
function help {
echo '''
Linux User Info
-h This help message.
-i User information, use as "-i user".
-x eXtended information.
-a List all users.
-l List all users with locked password.
-u List all users with unlocked password.
-n List users with nologin shell.
You can use multiple arguments too, eg. "./lui_deb.sh -l -u"
'''
}
function user_info {
data=$(grep ^$OPTARG: /etc/passwd)
if [ -z "$data" ]
then
echo "User not found in /etc/passwd."
exit ;
fi
user=$(echo $data | cut -d: -f1)
comment=$(grep ^$user /etc/passwd | cut -d: -f5)
if [ -z "$comment" ]
then
comment="-"
fi
home=$(echo $data | cut -d: -f6)
if [ -z "$home" ]
then
home="-"
fi
homepriv=$(ls -ld $home | awk {'print $1,$3,$4'})
if [ -z "$homepriv" ]
then
homepriv="Home directory does not exist."
fi
pass=$(passwd -S $OPTARG | cut -d' ' -f2-)
groups=$(groups $user | cut -d: -f2)
if [ -z "$groups" ]
then
groups="-"
fi
shell=$(echo $data | cut -d: -f7)
groupid=$(echo $data | cut -d: -f3)
ID=$(echo $data | cut -d: -f4)
echo
echo "User name: $user"
echo "Comment: $comment"
echo "Password: $pass"
echo "Home dir: $home"
echo "Home perm: $homepriv"
echo "Groups: $groups"
echo "Login shell: $shell"
echo "User ID: $ID"
echo "Group ID: $groupid"
echo
}
function eXtended {
#Experimental function!
echo
echo "User information"
echo "----------------"
user_info
chage -l $user | tr -d '\t'
echo
echo
echo "Login information"
echo -e "----------------- \n"
echo "Last four logins:"
last | grep $user | tail -4 | tr -s ' '
echo
fails=$(pam_tally --user $user | rev | cut -d ' ' -f1 | rev)
echo "Numer of failed logins: " $fails
echo
fail_list=$(grep sshd.\*Failed /var/log/auth.log | grep $user)
if [ ! -z "$fail_list" ]
then
echo "Last six login fails:"
grep sshd.\*Failed /var/log/auth.log | grep $user | tail -6
fi
}
function all_users {
min_uid=$(grep "^UID_MIN" /etc/login.defs | tr -s ' ' | cut -d' ' -f2)
echo "System users / Under UID $min_uid"
echo "---------------------------------"
awk -F':' -v "minuid=$min_uid" '{ if ( $3 < minuid ) print $0 }' /etc/passwd
grep nobody /etc/passwd
echo
echo "Normal users / Below UID $min_uid"
echo "---------------------------------"
awk -F':' -v "minuid=$min_uid" '{ if ( $3 >= minuid ) print $0 }' /etc/passwd | grep -v ^nobody:
echo
}
function locked_users {
echo "Locked users:"
cat /etc/passwd | cut -d : -f 1 | awk '{ system("passwd -S " $0) }' | grep -e "\sL\s"
echo
}
function unlocked_users {
echo "Unlocked users:"
cat /etc/passwd | cut -d : -f 1 | awk '{ system("passwd -S " $0) }' | grep -v -e "\sL\s"
echo
}
function nologin_users {
echo "Users with nologin:"
cat /etc/passwd | grep /nologin
echo
}
while getopts ":hi:x:alun" opt;
do
case $opt in
h) help ;;
i) user_info ;;
x) eXtended ;;
a) all_users ;;
l) locked_users ;;
u) unlocked_users ;;
n) nologin_users ;;
\?)
echo "Invalid option."
exit 1 ;;
:)
echo "Option -$OPTARG requires an argument." ;;
esac
done
if [ -z "$1" ]
then
help
fi
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